Evaluating Stresses and Forces in Fasteners

• So, with the following effective stress area estimates.. As = 0.1414 in2 Ats = 0.3458 in^2 …the predicted tensile load that results in a safety factor of 1.25 is… • For thread shear: Fts = Ats*1/sf* y/2 = 0.3458*.8*23206/2 = 3209.9 lbf • For tensile failure: Ft = As*1/sf* y = 0.1414*.8*23206 = 2625.1 lbf

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For Leaders: Supporting Your Staff During the Coronavirus

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(PDF) Stress Analysis Of Hot Wall Flue Gas Piping At FCCU

The bending stress is zero at the neutral axis and varies linearly across the cross section from maximum compressive to maximum tensile. SL = Mb * c/I Where, Mb = Moment of the beam. c = distance of point of interest from the neutral axis.

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